how much energy is needed to raise the temperature of 0.05kg of water from 20-60 degrees
60-20=40°C
0.05x4200x40=8400J
100
Do 40X40 For your answer
To calculate the energy required to raise the temperature of a substance, you need to use the formula:
Q = m * c * ΔT
where:
Q is the energy transfer (in Joules),
m is the mass of the substance (in kilograms),
c is the specific heat capacity of the substance (in J/kg·°C), and
ΔT is the change in temperature (in °C).
For water, the specific heat capacity is approximately 4.18 J/g·°C or 4180 J/kg·°C. However, you need to convert the mass of water from grams to kilograms, as the specific heat capacity is given in that unit.
Given:
m = 0.05 kg (mass of water)
c = 4180 J/kg·°C (specific heat capacity of water)
ΔT = 60°C - 20°C = 40°C (change in temperature)
First, let's convert the mass to kilograms:
0.05 kg = 50 g
Now we can substitute the values into the formula:
Q = (0.05 kg) * (4180 J/kg·°C) * (40°C)
Q = 8360 J
Therefore, it would take 8360 Joules of energy to raise the temperature of 0.05 kg of water from 20°C to 60°C.