How do you covert my/mL to M .eg covert 250 mg/L of paracetamol to M.
To convert milligrams per liter (mg/L) of a substance to molarity (M), you need to know the molar mass of the substance. Here's how you can convert 250 mg/L of paracetamol to M:
1. Find the molar mass of paracetamol:
The molar mass of paracetamol (C8H9NO2) can be calculated by adding up the atomic masses of its constituent elements. The atomic masses of carbon (C), hydrogen (H), nitrogen (N), and oxygen (O) are 12.01 g/mol, 1.008 g/mol, 14.01 g/mol, and 16.00 g/mol, respectively.
Molar mass of C8H9NO2 = (8 * 12.01) + (9 * 1.008) + 14.01 + (2 * 16.00) g/mol
= 56.08 + 9.072 + 14.01 + 32.00 g/mol
= 111.16 g/mol
2. Convert mg/L to g/L:
Since 1 mg = 0.001 g, you need to convert milligrams to grams.
250 mg/L = 250 * 0.001 g/L
= 0.25 g/L
3. Convert g/L to mol/L (M):
To convert grams per liter to moles per liter, divide by the molar mass.
Molar concentration (M) = (grams per liter) / (molar mass)
= 0.25 g/L / 111.16 g/mol
4. Simplify the units, if necessary:
In this case, you need to simplify the units by dividing the numerator and denominator by 0.25.
Molar concentration (M) = 0.25 g/L / 111.16 g/mol
= 1.792 x 10^-3 mol/L
Thus, 250 mg/L of paracetamol is approximately 1.792 x 10^-3 M.
simply 475/500
To simplify the fraction 475/500, you can divide both the numerator and the denominator by their greatest common factor, which in this case is 25:
475 ÷ 25 = 19
500 ÷ 25 = 20
Therefore, the simplified form of 475/500 is 19/20.
You toss a coin 50 times and get 12 tails. What is the empirical probability of getting
heads? Write your answer in percent form. (1 point)
76%
0.76
24%
19 25
The empirical probability of getting heads can be calculated by subtracting the number of tails from the total number of coin tosses, and then dividing it by the total number of coin tosses.
Total coin tosses: 50
Number of tails: 12
Number of heads: 50 - 12 = 38
Empirical probability of getting heads: 38/50 = 0.76
To express this probability in percent form, multiply it by 100:
0.76 * 100 = 76%
Therefore, the empirical probability of getting heads is 76%.
A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana. (1 point)
3/5
21/190
7/80
7/76
To calculate the probability of selecting an apple and a banana, we need to find the probability of selecting one apple and one banana out of the total fruits available.
Total fruits in the basket = 5 bananas + 8 mangoes + 7 apples = 20 fruits
Probability of selecting an apple as the first fruit:
P(apple) = 7/20
After selecting an apple, the total number of fruits remaining decreases to 19 (since one apple has been selected and not replaced).
Probability of selecting a banana as the second fruit:
P(banana) = 5/19
Since we are selecting the fruits without replacement, the probabilities are dependent events, meaning the probability of both events happening is the product of the individual probabilities.
Probability of selecting an apple and a banana = P(apple) * P(banana)
= (7/20) * (5/19)
= 35/380
= 7/76
Therefore, the probability of selecting an apple and a banana is 7/76.
simplfy 1500/2500
To simplify the fraction 1500/2500, we can divide both the numerator and the denominator by their greatest common factor, which in this case is 500:
1500 ÷ 500 = 3
2500 ÷ 500 = 5
Therefore, the simplified form of 1500/2500 is 3/5.
Candidate 1 has 250 voters
Candidate 2 has 1,250 voters
Candidate 3 has 450 voters
Candidate 4 has 550 voters
in total 2500 votes if 1000 more people voted how many would vote for Candidate 3 and Candidate 4