How do you covert my/mL to M .eg covert 250 mg/L of paracetamol to M.

To convert milligrams per liter (mg/L) of a substance to molarity (M), you need to know the molar mass of the substance. Here's how you can convert 250 mg/L of paracetamol to M:

1. Find the molar mass of paracetamol:
The molar mass of paracetamol (C8H9NO2) can be calculated by adding up the atomic masses of its constituent elements. The atomic masses of carbon (C), hydrogen (H), nitrogen (N), and oxygen (O) are 12.01 g/mol, 1.008 g/mol, 14.01 g/mol, and 16.00 g/mol, respectively.

Molar mass of C8H9NO2 = (8 * 12.01) + (9 * 1.008) + 14.01 + (2 * 16.00) g/mol
= 56.08 + 9.072 + 14.01 + 32.00 g/mol
= 111.16 g/mol

2. Convert mg/L to g/L:
Since 1 mg = 0.001 g, you need to convert milligrams to grams.

250 mg/L = 250 * 0.001 g/L
= 0.25 g/L

3. Convert g/L to mol/L (M):
To convert grams per liter to moles per liter, divide by the molar mass.

Molar concentration (M) = (grams per liter) / (molar mass)
= 0.25 g/L / 111.16 g/mol

4. Simplify the units, if necessary:
In this case, you need to simplify the units by dividing the numerator and denominator by 0.25.

Molar concentration (M) = 0.25 g/L / 111.16 g/mol
= 1.792 x 10^-3 mol/L

Thus, 250 mg/L of paracetamol is approximately 1.792 x 10^-3 M.

simply 475/500

To simplify the fraction 475/500, you can divide both the numerator and the denominator by their greatest common factor, which in this case is 25:

475 ÷ 25 = 19
500 ÷ 25 = 20

Therefore, the simplified form of 475/500 is 19/20.

You toss a coin 50 times and get 12 tails. What is the empirical probability of getting

heads? Write your answer in percent form. (1 point)
76%
0.76
24%
19 25

The empirical probability of getting heads can be calculated by subtracting the number of tails from the total number of coin tosses, and then dividing it by the total number of coin tosses.

Total coin tosses: 50
Number of tails: 12
Number of heads: 50 - 12 = 38

Empirical probability of getting heads: 38/50 = 0.76

To express this probability in percent form, multiply it by 100:

0.76 * 100 = 76%

Therefore, the empirical probability of getting heads is 76%.

A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana. (1 point)

3/5
21/190
7/80
7/76

To calculate the probability of selecting an apple and a banana, we need to find the probability of selecting one apple and one banana out of the total fruits available.

Total fruits in the basket = 5 bananas + 8 mangoes + 7 apples = 20 fruits

Probability of selecting an apple as the first fruit:
P(apple) = 7/20

After selecting an apple, the total number of fruits remaining decreases to 19 (since one apple has been selected and not replaced).

Probability of selecting a banana as the second fruit:
P(banana) = 5/19

Since we are selecting the fruits without replacement, the probabilities are dependent events, meaning the probability of both events happening is the product of the individual probabilities.

Probability of selecting an apple and a banana = P(apple) * P(banana)
= (7/20) * (5/19)
= 35/380
= 7/76

Therefore, the probability of selecting an apple and a banana is 7/76.

simplfy 1500/2500

To simplify the fraction 1500/2500, we can divide both the numerator and the denominator by their greatest common factor, which in this case is 500:

1500 ÷ 500 = 3
2500 ÷ 500 = 5

Therefore, the simplified form of 1500/2500 is 3/5.

Candidate 1 has 250 voters

Candidate 2 has 1,250 voters
Candidate 3 has 450 voters
Candidate 4 has 550 voters
in total 2500 votes if 1000 more people voted how many would vote for Candidate 3 and Candidate 4

To determine how many more voters would vote for Candidate 3 and Candidate 4 if 1000 more people voted, we need to calculate the proportion of votes each candidate currently has and apply that proportion to the additional 1000 votes.

First, calculate the total number of votes currently cast:

Total number of votes = Number of votes for Candidate 1 + Number of votes for Candidate 2 + Number of votes for Candidate 3 + Number of votes for Candidate 4
= 250 + 1250 + 450 + 550
= 2500

Next, calculate the proportion of votes each candidate currently has:

Proportion of votes for Candidate 3 = Number of votes for Candidate 3 / Total number of votes
= 450 / 2500
= 0.18

Proportion of votes for Candidate 4 = Number of votes for Candidate 4 / Total number of votes
= 550 / 2500
= 0.22

Now, determine the number of additional votes for Candidate 3 and Candidate 4 by multiplying their respective proportions by the additional 1000 votes:

Additional votes for Candidate 3 = Proportion of votes for Candidate 3 * 1000
= 0.18 * 1000
= 180

Additional votes for Candidate 4 = Proportion of votes for Candidate 4 * 1000
= 0.22 * 1000
= 220

Therefore, if 1000 more people voted, approximately 180 more votes would go to Candidate 3 and approximately 220 more votes would go to Candidate 4.

A basket of fruits contains 20 apples, 4 watermelon slices, and 12 oranges. If

a piece of fruit is to be selected randomly from the box, what is the probability
of selecting an apple or an orange? Explain the process you used.

To calculate the probability of selecting an apple or an orange, we need to determine the total number of favorable outcomes (apples or oranges) and divide it by the total number of possible outcomes (all the fruits in the basket).

Total number of apples = 20
Total number of oranges = 12
Total number of watermelon slices = 4

Total number of fruits = Number of apples + Number of oranges + Number of watermelon slices = 20 + 12 + 4 = 36

The probability of selecting an apple or an orange is given by:
P(apple or orange) = (Number of apples + Number of oranges) / Total number of fruits

Substituting the values:
P(apple or orange) = (20 + 12) / 36
= 32 / 36
= 8 / 9

Thus, the probability of selecting an apple or an orange is 8/9.

32/36 simplfy

To simplify the fraction 32/36, we can divide both the numerator and the denominator by their greatest common factor, which in this case is 4:

32 ÷ 4 = 8
36 ÷ 4 = 9

Therefore, the simplified form of 32/36 is 8/9.

A survey of 80 employees was conducted asking about which meals they

regularly eat at the office. Twenty employees eat breakfast at the office, 50
eat lunch, and 15 eat both breakfast and lunch. If an employee is randomly
selected from this group, what is the probability of randomly selecting an
employee who eat breakfast or lunch at the office? Explain how you got the
answer.

To calculate the probability of randomly selecting an employee who eats breakfast or lunch at the office, we need to determine the total number of favorable outcomes (employees who eat breakfast or lunch) and divide it by the total number of possible outcomes (total number of employees).

Total number of employees who eat breakfast = 20
Total number of employees who eat lunch = 50
Total number of employees who eat both breakfast and lunch = 15

To count the total number of employees who eat breakfast or lunch, we need to add the employees who eat breakfast, the employees who eat lunch, and subtract the employees who eat both breakfast and lunch.
Total number of employees who eat breakfast or lunch = (Total number of employees who eat breakfast) + (Total number of employees who eat lunch) - (Total number of employees who eat both breakfast and lunch)
= 20 + 50 - 15
= 55

Total number of employees = 80

The probability of randomly selecting an employee who eats breakfast or lunch is given by:
P(eat breakfast or lunch) = (Number of employees who eat breakfast or lunch) / (Total number of employees)

Substituting the values:
P(eat breakfast or lunch) = 55 / 80
= 11 / 16

Thus, the probability of randomly selecting an employee who eats breakfast or lunch at the office is 11/16.

Use an online spinner to generate a wheel with five equal sections. Use the

letters of the word CLEAN as the labels.
a. Use the spinner to simulate the random selection of two letters with
repetition from the word CLEAN. This will constitute one trial.
b. Conduct 150 trials. Summarize the results using a table.

apologies, but as a text-based AI, I'm unable to simulate a spinner or directly generate a table for you. However, I can guide you on how to conduct the simulation and summarize the results using a table:

a. Simulating the random selection of two letters with repetition:
- Assign a number or color to each section of the spinner corresponding to the letters C, L, E, A, and N of the word CLEAN.
- Spin the virtual spinner twice, recording the letter landed on in each spin.
- Repeat this process for a total of 150 trials (spinning the virtual spinner twice each time).

b. Summarizing the results using a table:
- Create a table with five columns representing the letters C, L, E, A, and N.
- Count the number of times each letter is obtained in the 150 trials and record it in the respective column.
- Calculate the frequency or percentage of occurrence for each letter by dividing the count by 150 and multiplying by 100 if desired.

After conducting the simulation and filling out the table, you will have a summary of the results showing the frequency or percentage of obtaining each letter during the 150 trials.

77/150 simplyfy

To simplify the fraction 77/150, we can divide both the numerator and the denominator by their greatest common factor, which in this case is 1:

77 ÷ 1 = 77
150 ÷ 1 = 150

Therefore, the simplified form of 77/150 is 77/150.

77/150 as a percent

To convert the fraction 77/150 to a percent, we can multiply it by 100:

77/150 * 100 = 51.33%

Therefore, the fraction 77/150 is approximately 51.33% when expressed as a percent.

60/150 simplifyed

To simplify the fraction 60/150, we can divide both the numerator and the denominator by their greatest common factor, which in this case is 30:

60 ÷ 30 = 2
150 ÷ 30 = 5

Therefore, the simplified form of 60/150 is 2/5.

1/2 times 1/6

To multiply fractions, you simply multiply the numerators together and the denominators together.

Therefore,

(1/2) * (1/6) = (1 * 1) / (2 * 6) = 1/12.

So, 1/2 multiplied by 1/6 is equal to 1/12.

make it more detailed and profecional.

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