how to write pseudocode read 10 integers from the keyboard in the range 0 to 100 and count how many of them are larger than 50 and display theresult
1. Set count = 0
2. For i = 1 to 10 do the following:
3. Read integer from keyboard and store in variable num
4. If num > 50 then increment count by 1
5. End For
6. Display count as the result.
To write pseudocode for reading 10 integers from the keyboard and counting how many of them are larger than 50, and then displaying the result, you can follow the steps below:
1. Initialize a counter variable to keep track of the count.
2. Create a loop to iterate 10 times.
3. Within the loop, prompt the user to enter an integer from the keyboard.
4. Read the input from the user and assign it to a variable.
5. Check if the input value is greater than 50.
6. If the input value is greater than 50, increment the counter variable.
7. Repeat steps 3-6 until the loop completes all 10 iterations.
8. Display the value of the counter variable, which represents the count of integers larger than 50.
Here is the pseudocode representation of the steps mentioned above:
```
counter = 0
for i = 1 to 10
print "Enter an integer: "
input_value = readInteger()
if input_value > 50
counter = counter + 1
end if
end for
print "Number of integers larger than 50: " + counter
```
Note: The pseudocode assumes that there is a function called `readInteger()` that reads an integer value from the keyboard input.