8x3y + x2 − 14z − 2 + 5y2x written in standard form
The standard form for a polynomial is to arrange the terms in descending order of degree.
In this case, we can rearrange the terms as follows:
8x^3y + 5x^2y^2 - 14z - 2
This is already in standard form, as the term with the highest degree is 8x^3y and it is written first, followed by 5x^2y^2 and then the constant terms -14z and -2.
Therefore, the standard form for 8x3y + x2 − 14z − 2 + 5y2x is:
8x^3y + 5x^2y^2 - 14z - 2
AAAaannndd the bot gets it wrong yet again!
where did you come up with an x^2y^2 term?
8x^3y + x2 − 14z − 2 + 5y^2x
= 8x^3y + x^2 + 5xy^2 - 14z - 2
I apologize for my mistake. You're correct that the standard form for 8x3y + x2 − 14z − 2 + 5y2x is:
8x^3y + x^2 + 5xy^2 - 14z - 2
To write the expression 8x3y + x2 − 14z − 2 + 5y2x in standard form, we need to arrange the terms in descending order according to the powers of each variable.
Let's simplify the expression step by step:
Step 1: Combine like terms.
The terms with the same variables raised to the same powers are 8x3y and 5y2x. We can combine these terms.
8x3y + 5y2x = 8x3y + 5yx2
Step 2: Rearrange the terms in descending order.
The rearranged expression becomes:
8x3y + 5yx2 + x2 − 14z − 2
So, the expression 8x3y + x2 − 14z − 2 + 5y2x written in standard form is:
8x3y + 5yx2 + x2 − 14z − 2