Subtract 12(z+4)−3(14z+1) . Use fractions in final form
To find the value of the expression, we need to distribute and combine like terms.
First, distribute 12 to (z+4) to get 12z + 48.
Then, distribute -3 to (14z+1) to get -42z - 3.
Now we can combine like terms.
12z - 42z + 48 - 3 = (12z - 42z) + (48 - 3) = -30z + 45.
Therefore, the final expression is -30z + 45.
To subtract 12(z+4) from -3(14z+1), we need to distribute the negative sign to each term inside the parentheses.
Starting with -3(14z+1), we can apply the distributive property to get -42z - 3.
Next, we subtract 12(z+4) from -42z - 3. Again, we distribute the 12 to each term inside the parentheses: 12z + 48.
Now we can combine like terms.
The original expression becomes -42z - 3 - (12z + 48).
To subtract, we distribute the negative sign to each term inside the parentheses: -42z - 3 - 12z - 48.
Combining like terms, we have -54z - 51 as our final answer.
To subtract the given expression, we need to distribute the coefficients outside the brackets to the terms inside. Let's go step by step:
First, distribute the 12 to (z + 4):
12(z + 4) = 12z + 48
Next, distribute the -3 to (14z + 1):
-3(14z + 1) = -42z - 3
Now, let's combine like terms. We have 12z and -42z as our only z terms:
12z - 42z = -30z
Similarly, we have 48 and -3 as our only constant terms:
48 - 3 = 45
Finally, we rewrite the simplified expression:
-30z + 45
To express the final answer in fraction form, we can rewrite -30z + 45 as a fraction over 1:
(-30z + 45)/1
This is the final answer in fraction form.