Calculate d pH of 0.00mol/dm³ tetraoxosulphate(vi)
Without more information, it is impossible to calculate the change in pH from adding 0.00 mol/dm³ of tetraoxosulphate (VI) to a solution. pH is a measure of the concentration of hydrogen ions in a solution, and the addition of another compound would require knowing the initial pH, the strength and acidity of the added compound, and the resulting chemical reaction that takes place.
To calculate the pH of a solution of tetraoxosulphate (VI), also known as sulfate, you need to know the concentration of the solution and the dissociation of the compound in water.
Since you have provided the concentration as 0.00 mol/dm³, it means that the solution is not dissociated and you have pure water.
The pH of pure water is 7. This is because water, in its purest form, is neutral. The pH scale ranges from 0 to 14, with values below 7 being acidic, 7 being neutral, and values above 7 being basic or alkaline.
Therefore, the pH of a 0.00 mol/dm³ tetraoxosulphate (VI) solution, which is essentially pure water, is 7.