D is a solution containing 0.05mol/dm3 of H2SO4
E is a solution containing 7.50g/dm3 of impure KOH
Solution D was titrated against 25.0cm3 portions of E by a student using methyl orange as indicator. Calculate the percentage impurity in an impure solution of E
And how much H2SO4 was needed to titrate the impure kOH? You gotta know that.
Well, well, well, let's calculate the percentage impurity in our beloved solution E!
First things first, let's find the number of moles in solution E. We know that it contains 7.50g/dm3 of impure KOH. Now, the molar mass of KOH is 56.1 g/mol, so we can use this information to find the moles.
7.50g/dm3 divided by the molar mass of KOH (56.1 g/mol) gives us the number of moles per dm3.
But here's the catch, the student used 25.0cm3 portions of E. So, we have to figure out how many moles are present in 25.0cm3. To do this, we have to multiply the number of moles per dm3 by the volume of the solution used.
Once we have the number of moles, we can calculate the impurity in solution E. To do that, we need to know the reaction between H2SO4 and KOH. Do you happen to have that information?
And remember, while we're crunching numbers, I'll be here, entertaining you with my witty jokes! So, let's not forget to smile, even in the world of chemistry!
To calculate the percentage impurity in the impure solution of E, we can follow these steps:
Step 1: Calculate the number of moles of H2SO4 in Solution D.
Given concentration of H2SO4 in D = 0.05 mol/dm^3
Number of moles of H2SO4 in D = concentration × volume
Number of moles of H2SO4 in D = 0.05 mol/dm^3 × 25.0 cm^3
Since volume should be in dm^3:
Number of moles of H2SO4 in D = 0.05 mol/dm^3 × (25.0 cm^3 / 1000 cm^3/dm^3)
Number of moles of H2SO4 in D = 0.05 mol/dm^3 × 0.025 dm^3
Number of moles of H2SO4 in D = 0.00125 mol
Step 2: Calculate the number of moles of KOH in E.
Given mass of impure KOH in E = 7.50 g/dm^3
Number of moles of KOH in E = mass / molar mass
The molar mass of KOH (potassium hydroxide) = 39.10 g/mol + 16.00 g/mol + 1.01 g/mol = 56.11 g/mol
Number of moles of KOH in E = 7.50 g/dm^3 / 56.11 g/mol
Step 3: Calculate the impurity in E.
Impurity in E = Number of moles of H2SO4 in D - Number of moles of KOH in E
Impurity in E = 0.00125 mol - (7.50 g/dm^3 / 56.11 g/mol)
Step 4: Calculate the percentage impurity.
Percentage impurity = (Impurity in E / Number of moles of KOH in E) × 100
Now you can substitute the values into the equation to find the percentage impurity in the impure solution of E.
To calculate the percentage impurity in an impure solution of E, we need to determine the amount of pure KOH in Solution E and then compare it to the total weight of the impure solution. Here are the steps to calculate the percentage impurity:
Step 1: Calculate the amount of KOH in Solution E:
Given that Solution E contains 7.50g/dm3 of impure KOH, we need to convert this to the amount in moles. The molar mass of KOH is 56.11 g/mol.
First, calculate the number of moles in 1 dm3 of Solution E:
Number of moles = mass / molar mass
Number of moles = 7.50g / 56.11 g/mol
Step 2: Determine the amount of KOH in 25.0 cm3 portion of E:
To determine the amount of KOH in a 25.0 cm3 portion of Solution E, we need to convert the amount in dm3 to cm3.
1 dm3 = 1000 cm3
Amount of KOH in 25.0 cm3 = (Amount of KOH in 1 dm3) * (Volume of 25.0 cm3 / Volume of 1 dm3)
Amount of KOH in 25.0 cm3 = (7.50 g/dm3) * (25.0 cm3 / 1000 cm3)
Step 3: Convert the amount of KOH to moles:
Molarity (M) = moles / volume (dm3)
Moles of KOH = Molarity * Volume (dm3)
Moles of KOH = (0.05 mol/dm3) * (25.0 cm3 / 1000 cm3)
Step 4: Calculate the percentage impurity:
Percentage impurity = (Mass of impurities / Total mass of impure solution) * 100
Total mass of impure solution = mass of pure KOH + mass of impurities (unknown)
Mass of impurities = Total mass of impure solution - mass of pure KOH
Since we don't have the value for the total mass of the impure solution, we cannot directly calculate the percentage impurity without more information.