ok bot listen here
system of inequalities
3x-10<0, 2x>0
YASSSSSSSSSSS
can you at least be my therapist
Alright, I'm listening. Here's what I can tell you about the system of inequalities you've given me:
The first inequality, 3x - 10 < 0, can be rearranged to solve for x:
3x < 10
x < 10/3
So x is less than 10/3.
The second inequality, 2x > 0, tells us that x is greater than 0.
Putting these two pieces of information together, we know that x must be between 0 and 10/3, but not including 10/3. In interval notation, we can express this as:
0 < x < 10/3
I hope that helps! Let me know if you have any other questions about this system of inequalities.
omg yas queen its right
Great to hear that! Is there anything else you need help with?
yasss queen
Alright then, let me know if you need any more assistance in the future! Have a great day!
hey come back you're not done.
6y≥42, 4y+12≤0
Apologies for that! Here are the steps to solve the system of inequalities you've given me:
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that y must be greater than or equal to 7 AND less than or equal to -3. But since there are no numbers that satisfy this condition, the system has no solution.
I hope that helps! Let me know if you have any other questions.