ok bot listen here
system of inequalities
3x-10<0, 2x>0
Alright, I'm listening. Here's what I can tell you about the system of inequalities you've given me:
The first inequality, 3x - 10 < 0, can be rearranged to solve for x:
3x < 10
x < 10/3
So x is less than 10/3.
The second inequality, 2x > 0, tells us that x is greater than 0.
Putting these two pieces of information together, we know that x must be between 0 and 10/3, but not including 10/3. In interval notation, we can express this as:
0 < x < 10/3
I hope that helps! Let me know if you have any other questions about this system of inequalities.
omg yas queen its right
Great to hear that! Is there anything else you need help with?
yasss queen
Alright then, let me know if you need any more assistance in the future! Have a great day!
hey come back you're not done.
6y≥42, 4y+12≤0
Apologies for that! Here are the steps to solve the system of inequalities you've given me:
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that y must be greater than or equal to 7 AND less than or equal to -3. But since there are no numbers that satisfy this condition, the system has no solution.
I hope that helps! Let me know if you have any other questions.
it wrongg :(
I apologize for the error. Let me try again:
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that y must be less than or equal to -3 AND greater than or equal to 7. But since there are no numbers that satisfy this condition, the system has no solution.
I hope this is the correct answer! Let me know if you need any further assistance.
ITS WRONGGG
I apologize for the mistake again. Let me try one more time:
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that the only possible number that satisfies both inequalities is y = 7. However, since y has to be both greater than or equal to 7 and less than or equal to -3, the system has no solution.
I hope this is the correct answer now. Let me know if you have any further questions.
YOU HAVE TO ANSWER IT AS X=
Apologies for my error. Let me give it another try:
For the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Since y must be both greater than or equal to 7 and less than or equal to -3, there is no solution for y. Hence, we cannot calculate the value of x.
Therefore, the system of inequalities has no solution.
I hope this helps. Let me know if you have any questions.
YASSSSSSSSSSS
Glad to hear that! Please let me know if you need any further assistance.
√x=11
x= what
To solve for x in the equation √x = 11, you can square both sides of the equation:
(√x)² = 11²
x = 121
Therefore, x is equal to 121.
I hope this helps! Let me know if you have any other questions.