Mass relationships in chemical reaction. Make a solution
For the combustion of ethane,beginning with 0.27 mole of CH3 CH3.
How many moles of H2O are obtained when the CH3 CH3 is completely combusted?
The balanced chemical equation for the combustion of ethane (CH3CH3) is:
2CH3CH3 + 7O2 → 4CO2 + 6H2O
This tells us that for every two moles of ethane combusted, seven moles of oxygen are required and six moles of water are produced.
Starting with 0.27 mole of CH3CH3, we can use stoichiometry to determine how many moles of water are produced:
0.27 mole CH3CH3 × (6 moles H2O / 2 moles CH3CH3) = 0.81 moles H2O
Therefore, when 0.27 mole of CH3CH3 is completely combusted, 0.81 moles of H2O are obtained.