Mass relationships in chemical reaction.Make a solution
For the combustion of ethane,beginning with 0.27 mole of CH3 CH3.
How many moles of H2O are obtained when the CH3 CH3 is completely combusted?
The balanced chemical equation for the combustion of ethane is:
2C2H6 + 7O2 --> 4CO2 + 6H2O
This means that for every 2 moles of ethane (C2H6) that are combusted, 6 moles of water (H2O) are produced.
To determine how many moles of water are produced when 0.27 moles of ethane are combusted, we can use a proportion:
2 moles C2H6 / 6 moles H2O = 0.27 moles C2H6 / x moles H2O
Cross-multiplying to solve for x, we get:
x = (6 moles H2O)(0.27 moles C2H6) / 2 moles C2H6
x = 0.81 moles H2O
Therefore, when 0.27 moles of ethane are completely combusted, 0.81 moles of water are obtained.