Bellstown Lewis City 120 km
Bellstown Jenkinsville 40 km
Jenkinsville Lewis City 60 km
Arturo creates a scale drawing showing these distances. If the distance between Lewis City and Bellstown is 6 centimeters on his drawing, how far apart are Lewis City and Jenkinsville on Arturo’s drawing?
The scale factor can be found by dividing the actual distance between Lewis City and Bellstown by the distance on the drawing:
120 km / 6 cm = 20 km/cm
Now, we can use this scale factor to find the distance between Lewis City and Jenkinsville on the drawing:
60 km / 20 km/cm = 3 cm
Therefore, Lewis City and Jenkinsville are 3 centimeters apart on Arturo's drawing.
We can use ratios to determine the length of the shorter side in Tiyane's scale drawing.
Let x be the length of the shorter side in Tiyane's drawing. Then:
9/22.5 = 3/x
Cross-multiplying:
9x = 67.5
Dividing both sides by 9:
x = 7.5
Therefore, the length of the parallelogram's shorter side in Tiyane's scale drawing is 7.5 inches.
Answer: 7.5 inches.
Tiyane makes a scale drawing of the parallelogram. The longer side of the parallelogram is 22.5 inches in her drawing. What is the length of the parallelogram’s shorter side in Tiyane’s scale drawing?
7.5 inches
60 inches
0.4 inches
2.5 inches
We cannot determine the length of the shorter side without additional information or the scale factor used for the drawing.
A parallelogram shows the longer side on the top measuring 9 inches and the shorter side on the right measuring 3 inches.
Without further information, we cannot determine the scale factor or use this information to create a scale drawing. Can you provide more details or the full question prompt?
Solve the following problem: Natalia prints a photo of a covered bridge. The print measures 6 centimeters by 4 centimeters. She wants to resize the photo into the size of a postcard with a length of 15 centimeters. What will be the area of the postcard?
Solve the following problem: Natalia prints a photo of a covered bridge. The print measures 6 centimeters by 4 centimeters. She wants to resize the photo into the size of a postcard with a length of 15 centimeters. What will be the area of the postcard?
2.5 square centimeters
60 square centimeters
150 square centimeters
24 square centimeters
wrong.
The area of the postcard can be found by multiplying the length and width of the postcard.
The length of the postcard is given as 15 centimeters. To find the width, we need to scale the width of the original photo by the same factor that we scaled the length.
The scaling factor is:
15 cm / 4 cm = 3.75
We scale the width of the original photo by multiplying it by 3.75:
4 cm x 3.75 = 15 cm
Therefore, the dimensions of the postcard are 15 cm by 22.5 cm.
The area of the postcard is:
15 cm x 22.5 cm = 337.5 square centimeters.
Therefore, the area of the postcard is 337.5 square centimeters.
Answer: 337.5 square centimeters.
Tiyane makes a scale drawing of the parallelogram. The longer side of the parallelogram is 22.5 inches in her drawing. What is the length of the parallelogram’s shorter side in Tiyane’s scale drawing?
7.5 inches
60 inches
0.4 inches
2.5 inches
Use the image to answer the question.
A parallelogram shows the longer side on the top measuring 9 inches and the shorter side on the right measuring 3 inches.
I apologize for my mistake in the previous response.
To scale the photo from 6 cm by 4 cm to fit within a postcard that is 15 cm long, we need to maintain the aspect ratio of the original photo. This means that we adjust both the length and width of the photo by the same scaling factor.
The scaling factor is determined by dividing the length of the postcard by the length of the original photo:
scaling factor = 15 cm / 4 cm = 3.75
Then, we multiply both the length and width of the original photo by the scaling factor to find the dimensions of the scaled photo:
length = 6 cm x 3.75 = 22.5 cm
width = 4 cm x 3.75 = 15 cm
The area of the postcard is then:
area = length x width = 22.5 cm x 15 cm = 337.5 cm²
Therefore, the area of the postcard will be 337.5 cm².
We can use proportions to determine the width of the postcard and then use the length and width to find the area.
Let x be the width of the postcard. Then:
6/4 = x/15
Cross-multiplying:
4x = 90
Dividing both sides by 4:
x = 22.5
Therefore, the dimensions of the postcard are 15 cm by 22.5 cm, and the area is:
15 cm x 22.5 cm = 337.5 cm²
Answer: The area of the postcard will be 337.5 cm².