A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?
• 40 N
• 8.2 N
• 1.6 N
• 7.8 N
We can use the formula F = ma, where F is the force, m is the mass, and a is the acceleration.
Given that the mass of the softball is 0.2 kg and the acceleration is 8 m/s^2, we can calculate the force as:
F = ma
F = 0.2 kg x 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N. The correct answer is option C.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s^2
Using the formula:
Force (F) = mass (m) * acceleration (a)
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the ball will hit the catcher's mitt with a force of 1.6 N. The correct answer is 1.6 N.