A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
Responses
7.8 N
7.8 N
1.6 N
1.6 N
40 N
40 N
8.2 N
The force with which the ball will hit the catcher's mitt can be calculated using Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a):
F = m * a
Plugging in the given values:
F = 0.2 kg * 8 m/s^2 = 1.6 N
Therefore, the ball will hit the catcher's mitt with a force of 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law formula:
Force = mass x acceleration
Given:
- mass of the softball = 0.2 kg
- acceleration of the softball = 8 m/s^2
Substituting these values into the formula:
Force = 0.2 kg x 8 m/s^2
Calculating the force:
Force = 1.6 N
Therefore, the ball will hit the catcher's mitt with a force of 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we need to use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a).
First, we need to find the mass of the softball, which is given as 0.2 kilograms.
Then, we are given that the ball is accelerating at a rate of 8 meters per second squared.
Using the formula F = ma, we can plug in the values:
F = 0.2 kg * 8 m/s^2
Multiplying these values together, we get:
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.