If a child accidentally swallowed 2 fluidounces of Feosol elixir containing 2/3 gr of ferrous sulphate per 5 mL, how many milligrams of ferrous sulphate did the child ingest? (5pts.)
To calculate the number of milligrams of ferrous sulfate the child ingested, we need to consider the concentration of ferrous sulfate in the Feosol elixir and the volume ingested.
Given:
- Feosol elixir contains 2/3 gr of ferrous sulfate per 5 mL.
- The child accidentally swallowed 2 fluid ounces.
First, we need to convert fluid ounces to milliliters since the concentration is given in milliliters.
1 fluid ounce is approximately equal to 29.57 milliliters (ml). Therefore, 2 fluid ounces would be 2 * 29.57 = 59.14 ml (rounded to two decimal places).
Next, we can calculate the amount of ferrous sulfate ingested using the concentration information.
We are told that 5 mL of Feosol elixir contains 2/3 gr of ferrous sulfate. To find the amount in milligrams (mg) instead of grains (gr), we need to convert 2/3 gr to milligrams.
1 gr is equal to approximately 64.799 milligrams (mg). So, we can calculate:
(2/3) gr * 64.799 mg/gr = 43.1993333... mg
Now, we know that 5 mL of Feosol elixir contains 43.1993333... mg of ferrous sulfate.
Since the child ingested 59.14 ml, we can set up a proportion:
(59.14 ml / 5 ml) = (x mg / 43.1993333... mg)
Simplifying the proportion, we have:
59.14 ml / 5 ml = x mg / 43.1993333...
Solving for x, we can multiply 59.14 by 43.1993333... and divide the result by 5:
x mg = (59.14 ml * 43.1993333...) / 5
Evaluating this expression, we find:
x mg ≈ 506.2159067...
Therefore, the child ingested approximately 506.22 milligrams of ferrous sulfate.