When 34.8grams of potassium sulphate was dissolved in 500cm cubed distilled water.calculate :the concentration of potassium sulphate in grams/litre.the molarity of the solution
Concentration in g/l
500/1000= 0.5 l
Therefore 34.8g/0.5 l= 69.6g/l
b)Molarity= no.of moles/volume in litre
No of moles= mass/molar mass of K2SO4
34.8/174= 0.198
M= 0.198/0.5= 0.396
you have the numbers and the units, so do the math.
1L = 1000cm^3, so 500cm^3 = 0.5L
34.8g / 0.5L = _____ g/L
To calculate the concentration of potassium sulphate in grams/liter, we can use the formula:
Concentration (g/L) = Mass of solute (g) / Volume of solution (L)
Given that the mass of potassium sulphate is 34.8 grams and the volume of the solution is 500 cm^3 (or 0.5 L), we can substitute these values into the formula:
Concentration (g/L) = 34.8 g / 0.5 L
Concentration (g/L) = 69.6 g/L
Therefore, the concentration of potassium sulphate in grams per liter is 69.6 g/L.
Now, let's calculate the molarity of the solution. Molarity is determined by the number of moles of solute present in one liter of solution. The formula to calculate molarity is:
Molarity (M) = Number of moles of solute / Volume of solution (in liters)
To calculate the molarity, we first need to determine the number of moles of potassium sulphate. We can use the molar mass of potassium sulphate to convert grams to moles.
The molar mass of potassium sulphate (K2SO4) is:
(2 x atomic mass of potassium (39.1 g/mol)) + (atomic mass of sulfur (32.1 g/mol)) + (4 x atomic mass of oxygen (16.0 g/mol))
Molar mass of K2SO4 = (2 x 39.1 g/mol) + 32.1 g/mol + (4 x 16.0 g/mol)
Molar mass of K2SO4 = 78.2 g/mol + 32.1 g/mol + 64.0 g/mol
Molar mass of K2SO4 = 174.3 g/mol
Now that we have the molar mass, we can calculate the number of moles of potassium sulphate:
Number of moles = Mass of solute (g) / Molar mass (g/mol)
Number of moles = 34.8 g / 174.3 g/mol
Number of moles = 0.1998 mol
Finally, we can substitute the values into the molarity formula:
Molarity (M) = Number of moles / Volume of solution (in liters)
Molarity (M) = 0.1998 mol / 0.5 L
Molarity (M) = 0.3996 M
Therefore, the molarity of the potassium sulphate solution is 0.3996 M.
Well, looks like we have some chemistry on our hands! How delightful!
Now, let's get down to business. To calculate the concentration of potassium sulphate in grams/liter, we need to convert the volume from cm³ to liters. 500 cm³ is equal to 0.5 liters.
Next, we divide the amount of potassium sulphate, which is 34.8 grams, by the volume in liters, which is 0.5 liters.
So, the concentration of potassium sulphate in grams/liter is 34.8 g/0.5 L, which simplifies to a hilarious 69.6 g/L. Yep, you heard it right.
Now, onto the molarity of the solution. Molarity is defined as the number of moles of solute per liter of solution. Since we have the mass of potassium sulphate, we need to convert that to moles by dividing it by its molar mass.
The molar mass of potassium sulphate (K₂SO₄) is approximately 174.26 g/mol. So, we divide the mass of potassium sulphate, 34.8 grams, by the molar mass to get the number of moles.
34.8 g / 174.26 g/mol ≈ 0.2 moles.
Finally, we divide the moles of potassium sulphate by the volume in liters to get the molarity of the solution.
0.2 moles / 0.5 L = a magnificent molarity of 0.4 M!
There you have it, my friend. The concentration is 69.6 g/L and the molarity is 0.4 M. Chemistry truly has a way of making things funny, doesn't it?
For molarity, M = mols/L. Convert 34.8 g K2SO4 to mols.
mols = g/molar mass = ?