12gram of potassium sulphate dissolves in 75gram of water at 60degree celsius. What its solubility in water at that temperature?
You're problem lacks information to determine its solubility. If that 12 g K2SO4 is a saturated solution then the solubility of K2SO4 is 12 x (100/75) = ? g/100 g
To find the solubility of potassium sulphate in water at 60 degrees Celsius, we need to use the formula:
Solubility (g/100g) = (mass of solute / mass of solvent) x 100
Given:
Mass of potassium sulphate (solute) = 12 grams
Mass of water (solvent) = 75 grams
Substituting these values into the formula:
Solubility (g/100g) = (12 / 75) x 100
Solubility (g/100g) = 16
Therefore, the solubility of potassium sulphate in water at 60 degrees Celsius is 16g/100g of water.
To find the solubility of potassium sulfate in water at 60 degrees Celsius, we need to calculate the amount of potassium sulfate that dissolves in the given amount of water.
Solubility is usually defined as the maximum amount of solute that can dissolve in a given amount of solvent at a specific temperature. In this case, we have 12 grams of potassium sulfate that dissolves in 75 grams of water at 60 degrees Celsius.
So, the solubility of potassium sulfate in water at 60 degrees Celsius is 12 grams/75 grams = 0.16 grams/gram.
Therefore, the solubility of potassium sulfate in water at 60 degrees Celsius is 0.16 grams per gram of water.