A game has 6 certain number of blue, red or black tokens. If you draw a token at random, the odds of getting a blue token are 1:2 and and the odds against getting a red token are 5:1.
a) If there are 32 blue tokens in this game, how many chips are there altogether?
b) If a against token is drawn at random, what are the odds of getting a black token ?
If there are 32,y,z blue, red, black tokens, respectively,
32/(y+z) = 1/2
(32+z)/y = 5/1
Now you should be able to answer the questions (if you can figure out what (b) actually means)
Sorry didnt get it and i got confused for both parts.
solve those equations and you find that there were
32 blue, 16 red, 48 black
you shouldn't have any trouble now with the questions ...
a) To find the total number of chips in the game, we need to determine the ratio of blue tokens to the total.
Given that the odds of getting a blue token are 1:2, it means that for every 1 blue token, there are 2 tokens in total.
Therefore, we can set up the following ratio:
1 blue : 2 total
Given that there are 32 blue tokens, we can write:
32 blue : 2 total
To determine the total number of tokens, we can use cross-multiplication.
32 * 2 = 64
Hence, there are a total of 64 tokens in the game.
b) To determine the odds of getting a black token if an against token is drawn at random, we need to consider the ratio of against tokens.
Given that the odds against getting a red token are 5:1, it means that for every 5 against tokens, there is 1 red token.
Therefore, we can set up the following ratio:
5 against : 1 red
Since we want to find the odds of getting a black token, we can consider that there are no specific odds or restrictions mentioned for black tokens.
Thus, the odds of getting a black token when an against token is drawn at random would be the same as the odds of getting any token that is not red, which includes the black tokens.
Therefore, the odds of getting a black token would be the same as the odds of getting any non-red token.