A weather balloon slowly expands as energy is transferred as heat from the outside air. If the average net pressure is 1.5×10^3 pa and the balloon's volume increases by 5.4×10^-5 m³, how much work is done by the expanding gas?
0.081J
To calculate the work done by the expanding gas, we can use the equation:
Work = Pressure * Change in Volume
Given:
Average net pressure = 1.5×10^3 Pa
Change in volume = 5.4×10^-5 m³
Substituting these values into the equation, we have:
Work = (1.5×10^3 Pa) * (5.4×10^-5 m³)
Now, let's calculate the work done by multiplying these values:
Work = (1.5×10^3) * (5.4×10^-5)
= 8.1×10^-2 Joules
Therefore, the work done by the expanding gas is 8.1×10^-2 Joules.
To determine the work done by the expanding gas, we need to use the formula:
Work = Pressure * Change in Volume
Given:
Pressure = 1.5 × 10^3 Pa
Change in volume = 5.4 × 10^-5 m³
Substituting the given values into the formula:
Work = (1.5 × 10^3 Pa) * (5.4 × 10^-5 m³)
Now, we can simplify and calculate the work done:
Work = (1.5 × 10^3) * (5.4 × 10^-5) Pa * m³
To multiply numbers in scientific notation, we multiply the coefficients and add the exponents:
Work = 8.1 × 10^-2 Pa * m³
Thus, the work done by the expanding gas is 8.1 × 10^-2 Pa * m³.