A gas collected at a temperature of 0C has a volume of 380 mL. At what temperature will the gas have a volume of 500 mL?
I have no idea how to solve this can someone help
Never mind I was looking at the other questions and this one has already been asked and answered
Thanks oobleck
PV = kT (where T is in °K)
since you apparently have a constant pressure, V/T is constant
So, you want T (in °C) such that
500/(273+T) = 380/(273+0)
To solve this problem, you can use the combined gas law. The combined gas law relates the pressure, volume, and temperature of a gas sample.
The combined gas law equation is:
P1 V1 / T1 = P2 V2 / T2
Where:
- P1 and P2 are the initial and final pressures of the gas (which we can assume are constant).
- V1 and V2 are the initial and final volumes of the gas.
- T1 and T2 are the initial and final temperatures of the gas.
In this case, we are given:
- V1 = 380 mL (the initial volume)
- V2 = 500 mL (the final volume)
- T1 = 0°C (the initial temperature)
We need to find T2, the final temperature of the gas.
To solve for T2, we can rearrange the combined gas law equation as follows:
T2 = (P2 * V2 * T1) / (P1 * V1)
Now, let's substitute the given values into the equation:
T2 = (P2 * 500 mL * 0°C) / (P1 * 380 mL)
Since we are not given any pressure values, we can assume that the pressure is constant and cancel out the P2 and P1 terms in the equation.
T2 = (500 mL * 0°C) / (380 mL)
Calculating this expression will give us the final temperature in degrees Celsius.