800cm3 of gas was collected at temperature of 33 degree and pressure of 500mmHg. Convert the volume of gas at S.T.P
760V/273.15 = 500*800/(33+273.15)
To convert the volume of gas to Standard Temperature and Pressure (STP), we can use the Ideal Gas Law. The Ideal Gas Law equation is given as PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
First, let's convert the given temperature from degrees Celsius to Kelvin (K). The Kelvin temperature scale is obtained by adding 273.15 to the Celsius temperature. So, the temperature in Kelvin is:
T = 33°C + 273.15 = 306.15 K
Next, we need to calculate the number of moles of gas using the ideal gas equation. Rearranging the equation, we can solve for n:
n = PV / RT
Substituting the given values into the equation:
P = 500 mmHg
V = 800 cm^3
T = 306.15 K
R = 0.0821 L·atm/(mol·K) (the ideal gas constant in the appropriate units)
Now we can calculate the number of moles (n) using the equation:
n = (500 mmHg * 800 cm^3) / (0.0821 L·atm/(mol·K) * 306.15 K)
Simplifying the units, we get:
n = (500 mmHg * 0.8 L) / (0.0821 L/mol·K * 306.15 K)
After performing the calculation and rounding to the appropriate number of significant figures, we find that n is approximately equal to 0.1251 moles.
Finally, we can use the ideal gas equation to calculate the volume of gas at standard temperature and pressure (STP). At STP, the temperature is 0°C or 273.15 K, and the pressure is 1 atmosphere (atm). Let's denote the new volume at STP as V_STP:
P_STP * V_STP = n * R * T_STP
Substituting the values:
P_STP = 1 atm
V_STP = ?
n = 0.1251 mol
R = 0.0821 L·atm/(mol·K)
T_STP = 273.15 K
Rearranging the equation and solving for V_STP:
V_STP = (n * R * T_STP) / P_STP
Substituting the values and performing the calculation:
V_STP = (0.1251 mol * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm
After performing the calculation and rounding to the appropriate number of significant figures, we find that V_STP is approximately equal to 2.45 L.
Therefore, the volume of the gas at standard temperature and pressure (STP) is approximately 2.45 liters.
To convert the volume of gas to Standard Temperature and Pressure (STP), we need to use the ideal gas law. The ideal gas law equation is represented as:
PV = nRT
Where:
P = pressure (in this case, in mmHg)
V = volume (in this case, in cm3)
n = number of moles of gas
R = ideal gas constant (0.0821 L·atm/mol·K or 62.36 L·mmHg/mol·K)
T = temperature (in this case, in Kelvin)
To convert the given gas volume to STP, we need to find the number of moles of the gas at the given conditions by rearranging the ideal gas law equation:
n = PV / RT
Now let's solve the equation step by step:
1. Convert the temperature from degrees Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 33 + 273.15
T(K) = 306.15 K
2. Convert the pressure from mmHg to atm by dividing it by 760:
P(atm) = P(mmHg) / 760
P(atm) = 500 / 760
P(atm) ≈ 0.6579 atm
3. Now, plug the values into the rearranged ideal gas law equation to find the number of moles of gas:
n = (P * V) / (R * T)
n = (0.6579 * 800) / (0.0821 * 306.15)
n ≈ 0.211 moles
To convert the volume of gas at STP, we need to determine the volume at 1 mole of an ideal gas at STP. At STP, 1 mole of gas occupies 22.4 liters. Therefore, the volume at STP can be calculated as follows:
Volume at STP = (Volume of gas * 22.4 L) / number of moles
Volume at STP = (800 * 22.4) / 0.211
Volume at STP ≈ 8521.33 cm3
So, the volume of the gas at STP is approximately 8521.33 cm3.