What volume of 0.704 M K3PO4 is required to
react with 48 mL of 0.975 M MgCl2 according
to the equation
2 K3PO4 + 3 MgCl2 → Mg3(PO4)2 + 6 KCl
Answer in units of mL.
I worked the same problem, but with different numbers, for Josh just a few questions above. Here is a link to get there. Post your work if you get stuck.
https://www.jiskha.com/questions/1865225/what-volume-of-0-649-m-k3po4-is-required-to-react-with-26-ml-of-0-453-m-mgcl2-according-to