what volume of 0.175 M NaP04 solution is required to react with 71.55 ml of 0.102 m CuCl2
Your question is confusing for more than one reason.
1. First sodium phosphate is Na3PO4.
2. Second you use 0.102 m CuCl2. m stands for molality. I'm sure you meant M. That means molarity.
3. You ask what volume is required to react with .... Actually, ANY volume will react with it. I expect you mean what volume Na3PO4 is required to react completely with CuCl2. That's what I will assume. The balanced equation is as follows:
2Na3PO4 + 3CuCl2 ==> Cu3(PO4)2(s) + 6NaCl
How many moles of CuCl2 do you have? That's M x L = 0.102 M x 0.07155 = 0.007298
How many moles of Na3PO4 will be needed? That's
0.007298 mols CuCl2 x (2 moles Na3PO4/3 moles CuCl2) =
0.007298 x 2/3 = 0.004865 moles Na3PO4.
Convert that to volume: moles = M x L. Substitute M from the problem, mols Na3PO4 from the calculation above and solve for L. Post your work if you get stuck.
To determine the volume of the NaP04 solution required to react with the CuCl2 solution, we need to use the concept of stoichiometry and the balanced chemical equation between NaP04 and CuCl2.
Firstly, let's write the balanced equation for the reaction:
2 Na3PO4 + 3 CuCl2 -> 6 NaCl + Cu3(PO4)2
From the equation, we can see that 2 moles of Na3PO4 react with 3 moles of CuCl2 to produce 6 moles of NaCl and 1 mole of Cu3(PO4)2.
Now, let's calculate the number of moles of CuCl2 in the given solution:
moles of CuCl2 = concentration of CuCl2 x volume of CuCl2 solution
= 0.102 M x 0.07155 L
= 0.0073146 moles
According to the stoichiometry in the balanced equation, 2 moles of Na3PO4 react with 3 moles of CuCl2. Therefore, the number of moles of Na3PO4 required for the reaction is:
moles of Na3PO4 = (3/2) x moles of CuCl2
= (3/2) x 0.0073146 moles
= 0.0109719 moles
Finally, let's calculate the volume of the NaP04 solution using its concentration:
volume of Na3PO4 solution = moles of Na3PO4 / concentration of Na3PO4
= 0.0109719 moles / 0.175 M
= 0.0626 L
= 62.6 mL
So, approximately 62.6 mL of 0.175 M NaP04 solution is required to react with 71.55 mL of 0.102 M CuCl2 solution.
To determine the volume of 0.175 M Na3PO4 solution needed to react with 71.55 ml of 0.102 M CuCl2, we can use the concept of stoichiometry.
First, we need to determine the balanced chemical equation for the reaction between Na3PO4 and CuCl2:
2 Na3PO4 + 3 CuCl2 → 6 NaCl + Cu3(PO4)2
From the balanced equation, we can see that the stoichiometric ratio of Na3PO4 to CuCl2 is 2:3. This means that for every 2 moles of Na3PO4, we need 3 moles of CuCl2.
Next, we can calculate the number of moles of CuCl2 in 71.55 ml of the 0.102 M solution:
Moles of CuCl2 = (Volume of CuCl2 solution in liters) x (Molarity of CuCl2 solution)
= 0.07155 L x 0.102 mol/L
= 0.0073091 mol
Now, using the stoichiometric ratio, we can determine the number of moles of Na3PO4 required to react with the calculated moles of CuCl2:
Moles of Na3PO4 = (Moles of CuCl2) x (2 moles of Na3PO4 / 3 moles of CuCl2)
= 0.0073091 mol x (2/3)
= 0.0048727 mol
Finally, we can calculate the volume of 0.175 M Na3PO4 solution needed to contain this amount of moles:
Volume of Na3PO4 solution = (Moles of Na3PO4 / Molarity of Na3PO4 solution)
= 0.0048727 mol / 0.175 mol/L
= 0.02784 L
= 27.84 ml
Therefore, approximately 27.84 ml of the 0.175 M Na3PO4 solution is required to react with 71.55 ml of 0.102 M CuCl2.