A car accelerated uniformly at 2.5 meters per second square starting from a velocity of 10 meters per second square calculate the final velocity
I don't know that ls why I ask
since acceleration is the rate of change of speed,
v changes by 2.5 m/s every second. That means that after t seconds,
v = 10 + 2.5t
since you did not say how long this went on, only you can provide the "final" velocity
Looks like you need to review velocity and acceleration
look at the units
a = m/s^2
so,
v = a*t = m/s^2 * s = m/s
To calculate the final velocity of the car, we can use the equation:
Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time (t))
Given:
- Initial velocity (u) = 10 m/s
- Acceleration (a) = 2.5 m/s²
Let's assume the time (t) is unknown, but we can solve for it using the formula:
Final velocity (v) = u + (a * t)
Rearranging the equation, we get:
t = (v - u) / a
Now, substituting the given values:
v = ? (the final velocity)
u = 10 m/s
a = 2.5 m/s²
We don't have the value of time (t) or the final velocity (v) yet. However, if we are given the time (t), we can calculate the final velocity.
If you have the value of time (t), you can calculate the final velocity by substituting all the known values into the equation. Let's say, for example, the time (t) is 6 seconds:
v = u + (a * t)
v = 10 + (2.5 * 6)
v = 10 + 15
v = 25 m/s
So, in this scenario, the final velocity of the car after 6 seconds would be 25 m/s.