Ama is four times as old as Akua in ten years time And will be twice as old as Akua find their ages
If Akua is x now, then
4x+10 = 2(x+10)
They are now 5 and 20
Please check wording.
Let's assume Akua's current age is A, and Ama's current age is M.
According to the given information, in ten years time, Ama's age will be M + 10, and Akua's age will be A + 10.
It is stated that Ama will be twice as old as Akua in ten years, so the equation can be formed as follows:
M + 10 = 2(A + 10)
Expanding the equation:
M + 10 = 2A + 20
Now, we know that Ama is four times as old as Akua. So, the equation can be formed as follows:
M = 4A
We have two equations, so we can solve them simultaneously to find their ages.
Substituting the value of M in the first equation:
4A = 2A + 10
Subtracting 2A from both sides:
4A - 2A = 10
Simplifying:
2A = 10
Dividing both sides by 2:
A = 10/2
A = 5
So, Akua's current age is 5.
Now, substituting A = 5 into the equation M = 4A:
M = 4(5)
M = 20
Therefore, Ama's current age is 20.
Hence, Akua is currently 5 years old, and Ama is currently 20 years old.
Let's assume the present age of Akua is A years and the present age of Ama is M years.
From the information given, we can form two equations:
1) Ama is four times as old as Akua in ten years time: M + 10 = 4(A + 10)
2) Ama will be twice as old as Akua in ten years time: M + 10 = 2(A + 10)
Now, let's solve the equations:
1) M + 10 = 4(A + 10)
M + 10 = 4A + 40
M = 4A + 40 - 10
M = 4A + 30
2) M + 10 = 2(A + 10)
M + 10 = 2A + 20
M = 2A + 20 - 10
M = 2A + 10
Since both equations are equal to M, we can set them equal to each other:
4A + 30 = 2A + 10
Now, solve for A:
4A - 2A = 10 - 30
2A = -20
A = -10
Since we cannot have a negative age, we know there must be an error in our initial assumptions or the information provided. Please double-check the given information.