Ama is four times as old as Akua. In ten years time, Ama will be twice as old as Akua. What is their ages.
let Ama's age be X and Akua's age be Y
first sentence
X=4Y.......(i)
second sentence
X+10=(Y+10)2......(ii)
substitute (i) into (ii)
4Y+10=2Y+20
collect like terms
4Y-2Y=20-10
2Y=10 divide both side by 2
2Y/2=10/2
Y=5
substitute Y into (i)
X=4*5
X=20
therefore Ama =20years and Akua=5years
Akua now --- x
Ama now ---- 4x
Akua in 10 years ---- x+10
Ama in 10 years ---- 4x+10
4x+10 = 2(x+10)
solve for x
Fantastic!!!
Ama is 4time as old as Akua. In 10year time Ama will twice as old as Akua find their ages
Akua now --- x
Ama now ---- 4x
Akua in 10 years ---- x+10
Ama in 10 years ---- 4x+10
4x+10 = 2(x+10)
solve for x
let Ama's age be X and Akua's age be Y
first sentence
X=4Y.......(i)
second sentence
X+10=(Y+10)2......(ii)
substitute (i) into (ii)
4Y+10=2Y+20
collect like terms
4Y-2Y=20-10
2Y=10 divide both side by 2
2Y/2=10/2
Y=5
substitute Y into (i)
X=4*5
X=20
therefore Ama =20years and Akua=5years
Thanks for your help and support
Let Ama age be X and Akua age be 4x
X =4x
4x +10=2(X+10)
4x+10 =2x+20
4x2x=20-10
2x =10
2 2
X=5
Yes, that's correct!
To solve this problem, we can set up a system of equations.
Let's assume Ama's current age is "x" years and Akua's current age is "y" years.
From the problem, we know that "Ama is four times as old as Akua," so we can write the equation: x = 4y.
We also know that "In ten years time, Ama will be twice as old as Akua," which can be represented as: x + 10 = 2(y + 10).
To solve this system of equations, we can substitute the first equation into the second equation:
4y + 10 = 2(y + 10).
Now, let's solve for y:
4y + 10 = 2y + 20.
Subtract 2y from both sides and subtract 10 from both sides:
4y - 2y = 20 - 10,
2y = 10.
Divide both sides by 2:
y = 5.
Now, substitute the value of y back into the first equation to find x:
x = 4 * 5 = 20.
Therefore, Ama is 20 years old and Akua is 5 years old.