How many total atoms are in 0.630 g of P2O5?
1 mol of P2O5 has a mass of 2*31 + 5*16 = 142 g so 0.630 grams is how much of a mole? That's 0.630/142 = 0.00444 mols P2O5. 1 mole P2O5 contains 0.00444 x 6.02E23 P2O5 molecules. So number of atoms is 7 times that.
Well, let's find out! P2O5 is the chemical formula for diphosphorus pentoxide. To figure out the number of atoms, we need to use some molar mass magic and Avogadro's number. But before we dive into calculations, let me tell you a joke to lighten the mood—Why did the scarecrow win an award? Because he was outstanding in his field!
Now, back to chemistry. The molar mass of P2O5 can be calculated as follows:
(2 × molar mass of P) + (5 × molar mass of O)
Now, the atomic masses of phosphorus (P) and oxygen (O) are approximately 31.0 g/mol and 16.0 g/mol, respectively. Plugging those values into the equation:
(2 × 31.0 g/mol) + (5 × 16.0 g/mol) = 62.0 g/mol + 80.0 g/mol = 142.0 g/mol
So now we know that one mole of P2O5 weighs 142.0 grams. To find the number of moles in 0.630 g, we divide the weight by the molar mass:
0.630 g / 142.0 g/mol = 0.00443 mol
Finally, we multiply the number of moles by Avogadro's number (6.02 × 10^23) to find the number of atoms:
0.00443 mol × 6.02 × 10^23 atoms/mol ≈ 2.66 × 10^21 atoms
So, in 0.630 g of P2O5, there are approximately 2.66 × 10^21 atoms. But hey, don't worry about counting them all by hand! Life's too short for that.
To calculate the total number of atoms in 0.630 g of P2O5, we need to use the molar mass and Avogadro's number.
First, let's calculate the number of moles of P2O5:
Molar mass of P2O5:
(2 * molar mass of P) + (5 * molar mass of O)
Molar mass of P = 30.97 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of P2O5 = (2 * 30.97 g/mol) + (5 * 16.00 g/mol)
Molar mass of P2O5 = 62.00 g/mol
Now, we can calculate the number of moles of P2O5:
Number of moles = mass / molar mass
Number of moles = 0.630 g / 62.00 g/mol
Number of moles of P2O5 ≈ 0.010161 mol
Next, we can use Avogadro's number to calculate the total number of molecules or atoms of P2O5:
Avogadro's number = 6.022 × 10^23 mol^-1
Total number of atoms = Number of moles * Avogadro's number
Total number of atoms ≈ 0.010161 mol * 6.022 × 10^23 mol^-1
Total number of atoms ≈ 6.118 × 10^21 atoms
Therefore, there are approximately 6.118 × 10^21 atoms in 0.630 g of P2O5.
To determine the total number of atoms in 0.630 g of P2O5, you need to follow these steps:
Step 1: Find the molar mass of P2O5
P2O5 is a compound composed of 2 atoms of phosphorus (P) and 5 atoms of oxygen (O). To calculate the molar mass of P2O5, you need to find the atomic mass of each element from the periodic table and multiply it by the number of atoms present.
The atomic mass of phosphorus (P) is 30.97 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol. Thus, the molar mass of P2O5 is:
(2 x atomic mass of P) + (5 x atomic mass of O)
= (2 x 30.97 g/mol) + (5 x 16.00 g/mol)
= 61.94 g/mol + 80.00 g/mol
= 141.94 g/mol
Step 2: Convert grams to moles
Divide the given mass (0.630 g) by the molar mass of P2O5 (141.94 g/mol) to get the number of moles.
0.630 g / 141.94 g/mol ≈ 0.00443 mol
Step 3: Calculate the number of atoms
Finally, you need to use Avogadro's number, which states that there are 6.022 x 10^23 atoms in one mole of any substance.
Multiply the number of moles (0.00443 mol) by Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms.
0.00443 mol x 6.022 x 10^23 atoms/mol ≈ 2.666 x 10^21 atoms
Therefore, there are approximately 2.666 x 10^21 atoms in 0.630 g of P2O5.