How many moles of P2O5 contain 3.68*1025 phosphorus atom? The
molar mass of P2O5 is 283.89 g/mol.
Is that 6.023*10^26 a typo meant to be 6.023*10^23?
yes, it was.
dunno what I was thinking ...
I'm sure @moly can make the adjustment ...
Sometimes the fingers have a mind of their own and they don't go where we tell them to go.
To calculate the number of moles of P2O5 containing 3.68*10^25 phosphorus atoms, we need to use the Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles.
First, we need to find the number of moles of phosphorus atoms in 3.68*10^25. Since there are two phosphorus atoms in one molecule of P2O5, we can divide the given number of phosphorus atoms by 2:
Number of moles of phosphorus atoms = (3.68*10^25 atoms) / 2
Next, we need to convert the number of moles of phosphorus atoms to moles of P2O5. Since there are 2 phosphorus atoms in one molecule of P2O5, we can use the ratio:
Number of moles of P2O5 = (Number of moles of phosphorus atoms) / 2
Finally, we can calculate the number of moles of P2O5 by dividing the number of moles of phosphorus atoms by 2 again.
Number of moles of P2O5 = (3.68*10^25 atoms / 2) / 2
Now we can substitute the values and calculate the result:
Number of moles of P2O5 = (3.68*10^25 / 2) / 2
= 3.68*10^25 / 4
= 9.2 * 10^24
Therefore, there are 9.2 * 10^24 moles of P2O5 containing 3.68*10^25 phosphorus atoms.
3.68*10^25 / 6.023*10^26 = 0.061 moles
so 0.061/2 = 0.0305 moles of P2O5 will have that many P atoms