10 people preferred drink a
15 people preferred drink b
07 people preferred drink c
03 people preferred drink d
06 people preferred drink e
so what is the probability that 1 shopper wouldn't prefer drink e or c?
A total of 41 people were polled.
28 would not prefer e or c.
28/41 would not prefer e or c
wait i asked my question wrong i meant a random shopper that wasn't polled
The answer is still the same. We have no idea what the random shopper would prefer so we have to look at it statistically.
ok thanks Ms. Sue
You're welcome.
To find the probability that one shopper wouldn't prefer drink e or c, we first need to calculate the total number of people who preferred drink e or c. Then, we can subtract this number from the total number of shoppers to find the number of shoppers who wouldn't prefer drink e or c.
Let's calculate the total number of people who preferred drink e or c:
Number of people who preferred drink e = 6
Number of people who preferred drink c = 7
Total number of people who preferred drink e or c = 6 + 7 = 13
Now, let's find the number of shoppers who wouldn't prefer drink e or c:
Total number of shoppers = 10 + 15 + 7 + 3 + 6 = 41
Number of shoppers who wouldn't prefer drink e or c = Total number of shoppers - Total number of people who preferred drink e or c
= 41 - 13
= 28
So, the probability that one shopper wouldn't prefer drink e or c is given by:
Probability = Number of shoppers who wouldn't prefer drink e or c / Total number of shoppers
= 28 / 41
≈ 0.6829 or 68.29%
Therefore, the probability that one shopper wouldn't prefer drink e or c is approximately 68.29%.