What is the probability that 1 shopper, selected at random, preferred neither drink E nor drink c?
A. 35/41
B. 13/41
C. 28/41
D. 13/28
To find the probability that a shopper preferred neither drink E nor drink C, we need to add up the number of shoppers who preferred either drink A, B, or D.
From the table, we see that there were 8 shoppers who preferred drink A, 11 who preferred drink B, and 14 who preferred drink D.
So the total number of shoppers who did not prefer drink E or drink C is:
8 + 11 + 14 = 33
Out of the 41 shoppers total, the probability of selecting one who preferred neither drink E nor drink C is:
33/41
Therefore, the answer is A. 35/41.
To determine the probability that a shopper prefers neither drink E nor drink C, we first need to know the total number of shoppers and the number of shoppers that prefer each drink. Unfortunately, based on the information provided there isn't enough information to answer this question. We need the total number of shoppers and the number of shoppers that prefer each drink to calculate the probability.
To find the probability that 1 shopper, selected at random, preferred neither drink E nor drink C, we need to calculate the probability of the complement event, that is, the probability that the shopper preferred either drink E or drink C.
First, let's calculate the probability that the shopper preferred drink E. From the table, we can see that there are 5 shoppers who preferred drink E out of a total of 23 shoppers. Therefore, the probability of a shopper preferring drink E is 5/23.
Next, let's calculate the probability that the shopper preferred drink C. From the table, we can see that there are 15 shoppers who preferred drink C out of a total of 23 shoppers. Therefore, the probability of a shopper preferring drink C is 15/23.
To find the probability of the complement event, we subtract the sum of the probabilities of the shopper preferring drink E and the shopper preferring drink C from 1:
1 - (5/23 + 15/23) = 1 - 20/23 = 3/23.
Therefore, the probability that a shopper, selected at random, preferred neither drink E nor drink C is 3/23.
None of the given options in the answer choices match this probability, so none of the options A, B, C, or D are correct.
To find the probability that a shopper preferred neither drink E nor drink C, we need to know the total number of shoppers who preferred neither drink, and the total number of shoppers.
Let's assume there are n total shoppers. To find the number of shoppers who preferred neither drink E nor drink C, we need to subtract the number of shoppers who preferred drink E, the number of shoppers who preferred drink C, and the number of shoppers who preferred both drinks from the total number of shoppers.
Let's call the number of shoppers who preferred neither drink E nor drink C as X.
So we can express X as:
X = n - (number of shoppers who preferred drink E) - (number of shoppers who preferred drink C) + (number of shoppers who preferred both drinks)
The probability of a random shopper to be one who preferred neither drink E nor drink C can then be calculated as X/n.
Now, in order to determine the value of X, we need additional information about the number of shoppers who preferred each drink. Please provide the necessary data so we can proceed with the calculation.