A scooter acquires a velocity of 30km/hr in 10 seconds just after the start.it takes 20 seconds to stop.calculate the acceleration in the two cases
In 1st case
v=10m/s
u=0m/s
t=10sec
equation= v=u+at
10=0+a(10)
10=a(10)
a=10/10
a=1m/s
In 2nd case
v=0m/s
u=10m/s
t=20sec
equation will be same v=u+at
0=10+a(20)
-10=a(20)
a=-10/20
a=-0.5m/s
Thnxx
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start: a = v/t = 30km/hr/10s = 3km/hr/s
If you like, you can convert km/hr to m/s and your answer will be the usual m/s^2.
since it takes twice as long to stop, the acceleration is half as much. And negative.
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Nice 👍👍
But yeh kaise kiya
To calculate acceleration, you need to use the formula:
Acceleration = (Final Velocity - Initial Velocity) / Time
In the first case, where the scooter acquires a velocity of 30 km/hr (or 8.33 m/s) in 10 seconds, you can calculate the acceleration as follows:
Acceleration = (8.33 m/s - 0 m/s) / 10 s
Acceleration = 0.833 m/s²
So, the acceleration in the first case is 0.833 m/s².
In the second case, where the scooter takes 20 seconds to stop, you can calculate the acceleration as follows:
Acceleration = (0 m/s - 8.33 m/s) / 20 s
Acceleration = -0.416 m/s²
The negative sign indicates that the scooter is decelerating, or slowing down. So, the acceleration in the second case is -0.416 m/s².