A constant force acts on a 5.0kg scooter and reduces its velocity from 7.0m/s to 3.0m/s in 3.00s. What is the net force on the scooter?
To find the net force acting on the scooter, we will use Newton's second law of motion, which states that the net force on an object is equal to the mass of the object multiplied by its acceleration.
First, let's calculate the acceleration of the scooter. We can use the equation:
acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 7.0 m/s
Final velocity (v) = 3.0 m/s
Time (t) = 3.00 s
acceleration = (3.0 m/s - 7.0 m/s) / 3.00s
acceleration = -4.0 m/s / 3.00s
acceleration = -1.33 m/s²
Now that we have the acceleration, we can calculate the net force on the scooter using the equation:
net force = mass * acceleration
Given:
mass (m) = 5.0 kg
acceleration (a) = -1.33 m/s²
net force = 5.0 kg * (-1.33 m/s²)
net force = -6.65 N
Therefore, the net force acting on the scooter is -6.65 N.
To find the net force acting on the scooter, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this case, we know the mass of the scooter is 5.0 kg and it undergoes a change in velocity from 7.0 m/s to 3.0 m/s in a time of 3.00 seconds. To determine the acceleration, we can use the following equation:
acceleration = (change in velocity) / time
acceleration = (3.0 m/s - 7.0 m/s) / 3.00 s
acceleration = -4.0 m/s / 3.00 s
acceleration = -1.33 m/s²
Since the scooter is decelerating (velocity is decreasing), the acceleration is negative.
Now that we have the mass (m = 5.0 kg) and acceleration (a = -1.33 m/s²), we can find the net force using Newton's second law:
force = mass × acceleration
force = 5.0 kg × (-1.33 m/s²)
force = -6.65 N
The net force acting on the scooter is -6.65 N. The negative sign indicates that the force is acting in the opposite direction of the scooter's motion.