At what height above the ground must a body of mass 10kg be situated inorder to have potential energy equal in value to the kinetic energy possessed by another body of mass 10kg moving with a velocity of 10m/s?
you want h such that (assuming g=10 m/s^2)
mgh = 1.2 mv^2
(10)(10)(h) = (1/2)(10)(10^2)
h = 5m
5m
5m
How is the answer 5m please 🥺🙏
Jeremiah wisdom
That's correct
Correct
Am seriously looking for the formula for this particular question
To determine the height at which a body must be situated in order to have potential energy equal to the kinetic energy of another body, we need to use the principles of potential energy and kinetic energy.
The potential energy (PE) of an object is given by the formula:
PE = mgh
where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height above the ground.
The kinetic energy (KE) of an object is given by the formula:
KE = (1/2)mv^2
where m is the mass of the object, and v is the velocity.
Given:
Mass of both bodies: m = 10 kg
Velocity of the second body: v = 10 m/s
Since we want to find the height (h) at which the potential energy is equal to the kinetic energy, we can set up an equation:
PE = KE
mgh = (1/2)mv^2
Canceling out the common terms (mass) on both sides, we get:
gh = (1/2)v^2
Now we can substitute the given values into the equation:
(9.8 m/s^2)h = (1/2)(10 m/s)^2
Simplifying the equation:
9.8h = 50
Dividing both sides by 9.8:
h = 50/9.8
Calculating the value:
h ≈ 5.10 meters
Therefore, a body of mass 10 kg must be situated at a height of approximately 5.10 meters above the ground to have potential energy equal to the kinetic energy of another body of mass 10 kg moving with a velocity of 10 m/s.