A stone of mass 10kg fall from the height of 2m.calculate the workdone
work = PE lost = mgh
A stone of mass 10kg falls from a height of 2m calculate the work done
I will love to look into it thanks
Well, let's calculate the work done by this falling stone. But first, I must ask: did the stone remember to bring its calculator? Because I'm afraid I might have to subtract some points for not showing its work.
Anyway, back to the problem. The work done by the stone is equal to the force applied multiplied by the distance traveled. In this case, the force is equal to the weight of the stone, which is its mass times the acceleration due to gravity. On Earth, the acceleration due to gravity is about 9.8 m/s², but let's round it up to a nice 10 m/s², because, you know, math should always be as smooth as possible.
So, the weight of the stone is 10 kg multiplied by 10 m/s², which is 100 N (Newtons). N as in "Not-the-Nobel-Prize-for-Mathematics".
Now, let's calculate the distance traveled, which is given as 2m. 2m? That's not a bad height to fall from. I mean, it's not Everest, but hey, nobody's judging here.
Finally, we multiply the force (100 N) by the distance traveled (2m). That gives us a grand total of 200 Joules. Can I get a drumroll, please? *Ba-dum-tss*
So, the work done by the stone is 200 Joules. Hey, at least it managed to get some work done while just falling. I applaud its productivity.
To calculate the work done, we can use the formula:
Work = Force × Distance × cos(θ)
In this case, we can assume that the force acting on the stone is its weight, which can be calculated using the formula:
Force = mass × acceleration due to gravity
Here, the mass of the stone is given as 10 kg. The acceleration due to gravity is typically taken as 9.8 m/s^2.
So, the force on the stone can be calculated as:
Force = 10 kg × 9.8 m/s^2 = 98 N
Now, we can calculate the work done. The distance the stone falls is given as 2 m. The angle, θ, between the force and the direction of displacement is 0 degrees since the force and displacement are in the same direction.
Thus, the work done is:
Work = 98 N × 2 m × cos(0°)
cos(0°) = 1, so the equation simplifies to:
Work = 98 N × 2 m × 1 = 196 J (Joules)
Therefore, the work done by the stone as it falls from a height of 2 m is 196 Joules.