If 5.29 g of CuNO3 is dissolved in water to make a 0.370 M solution, what is the volume of the solution?
I assume you really meant CuNO3 and not Cu(NO3)2.
mols CuNO3 = grams/molar mass = ?
Then M CuNO3 = mols CuNO3/L CuNO3 solution. You know M and mols, solve for L.
To find the volume of the solution, we can use the equation:
Molarity (M) = Moles (mol) / Volume (L)
First, we need to find the number of moles of CuNO3.
To do this, we can use the formula:
Moles (mol) = Mass (g) / Molar mass (g/mol)
The molar mass of CuNO3 can be calculated by adding up the atomic masses of copper (Cu), nitrogen (N), and three oxygen (O) atoms:
Cu: 63.55 g/mol
N: 14.01 g/mol
O (3 atoms): 16.00 g/mol × 3 = 48.00 g/mol
Molar mass of CuNO3 = 63.55 g/mol + 14.01 g/mol + 48.00 g/mol = 125.56 g/mol
Now we can calculate the number of moles:
Moles (mol) = 5.29 g / 125.56 g/mol
Next, we can use the molarity equation to find the volume of the solution:
0.370 M = Moles (mol) / Volume (L)
Rearranging the equation to solve for volume:
Volume (L) = Moles (mol) / Molarity (M)
Now we can substitute the values we found into the equation:
Volume (L) = (5.29 g / 125.56 g/mol) / 0.370 mol/L
Calculating the value:
Volume (L) = 0.113 L
Therefore, the volume of the solution is 0.113 L (or 113 mL).