10.0 g of NH4NO3 is dissolved in enough water to make 450.0 mL of solution. What is the molarity of the solution?
a number of ways to do this
he must have put 1/10 of 10.8g in the sample, then diluted it to a volume of .050liters
Molarity=10.8/10 * 1/molmass*1/.050
where molmass is the molmass of ammonium nitrate.
NOPE, that is not one of the ways to do this problem. The correct way to do this is as follows:
M = mols/L of solution. L is 0.45 from the problem. Find mols by
moles = grams/molar mass = 10.8/80 = xx
So M = mols/L = xx from above/0.45 = ?
To find the molarity of a solution, we need to know the moles of solute and the volume of the solution.
Step 1: Calculate the moles of NH4NO3.
The molar mass of NH4NO3 can be calculated by adding up the atomic masses of each element in the formula:
Molar mass of NH4NO3 = (1 x atomic mass of N) + (4 x atomic mass of H) + (3 x atomic mass of O)
The atomic masses are as follows:
Atomic mass of N = 14.01 g/mol
Atomic mass of H = 1.01 g/mol
Atomic mass of O = 16.00 g/mol
Molar mass of NH4NO3 = (1 x 14.01) + (4 x 1.01) + (3 x 16.00) = 80.04 g/mol
To calculate the moles of NH4NO3, we use the formula:
moles = mass / molar mass
moles of NH4NO3 = 10.0 g / 80.04 g/mol = 0.125 mol
Step 2: Find the volume of the solution in liters.
We are given that the volume is 450.0 mL. To convert it to liters, we divide by 1000:
volume of solution = 450.0 mL / 1000 mL/L = 0.450 L
Step 3: Calculate the molarity using the formula:
Molarity (M) = moles / volume
Molarity of the solution = 0.125 mol / 0.450 L ≈ 0.278 M
Therefore, the molarity of the solution is approximately 0.278 M.
To find the molarity of a solution, we need to know the amount of solute (NH4NO3) in moles and the volume of the solution in liters.
First, let's determine the amount of NH4NO3 in moles. We can use the formula:
moles = mass / molar mass
The molar mass of NH4NO3 can be calculated by adding up the atomic masses of each element in the compound:
molar mass of NH4NO3 = (molar mass of N + 4 * molar mass of H + 3 * molar mass of O)
Using the atomic masses from the periodic table, we find:
molar mass of NH4NO3 = (14.01 g/mol + 4 * 1.01 g/mol + 3 * 16.00 g/mol)
Now we can substitute the values into the formula for moles:
moles = 10.0 g / molar mass of NH4NO3
Next, we need to convert the volume of the solution from milliliters to liters. Since there are 1000 milliliters in a liter, we have:
volume (in liters) = 450.0 mL / 1000
Finally, we can calculate the molarity using the formula:
molarity = moles / volume (in liters)
Substitute the values and calculate:
molarity = moles / (volume (in liters))
Now you have the steps to find the molarity of the solution. Just substitute the values for mass and volume to get your final answer.