Chemistry,what is the k.e of 4 moles of nitrogen gas at 127 degree centigrade?
To calculate the kinetic energy (KE) of a gas, we can use the formula:
KE = (3/2) * n * R * T
Where:
- KE is the kinetic energy in Joules (J)
- n is the number of moles of the gas
- R is the gas constant, which is 8.314 J/(mol·K)
- T is the temperature in Kelvin (K)
Given:
- n = 4 moles
- T = 127 degrees Celsius = 127 + 273 = 400 K
Now, we can substitute the values into the formula and calculate the kinetic energy:
KE = (3/2) * 4 * 8.314 * 400
= 6 * 8.314 * 400
= 199056 J
Therefore, the kinetic energy of 4 moles of nitrogen gas at 127 degrees Celsius is approximately 199,056 Joules.