If 7.63 g of CuNO3 is dissolved in water to make a 0.180 M solution, what is the volume of the solution?
I wonder if that is Cu(NO3)2.
mols = grams/molar mass.
Then M = mols/l. mols is ? from above. Solve for L. You know m = 0.180
CopperI nitrate has never been isolated outside of water solutions, so it would be very difficult to disolve ;7.63 grams of it.
I would assume CopperII nitrate also
To find the volume of the solution, we can rearrange the formula for molarity (M):
M = moles of solute / volume of solution in liters
In this case, we are given the mass of the solute (CuNO3) and the molarity (0.180 M), so we can use this information to find the volume of the solution.
First, we need to calculate the moles of the solute (CuNO3). To do this, we can use the formula:
moles = mass / molar mass
The molar mass of CuNO3 can be calculated by summing the atomic masses of its individual elements:
Cu: 63.55 g/mol
N: 14.01 g/mol
O: 16.00 g/mol (x 3 because there are three oxygen atoms in CuNO3)
Molar mass of CuNO3 = 63.55 + 14.01 + (16.00 x 3) = 187.55 g/mol
Now we can calculate the moles of CuNO3:
moles = 7.63 g / 187.55 g/mol
Next, we can use the formula for molarity to find the volume of the solution:
M = moles / volume
0.180 M = moles / volume
To solve for the volume, we rearrange the equation:
volume = moles / M
volume = (7.63 g / 187.55 g/mol) / 0.180 M
Now we can perform the calculations to find the volume of the solution.