MATH
posted by heather .
Given that x=logbase3 5 and
y=logbase3 2 , rewrite logbase3 60 in terms of x and y.

given:
x = log_{3} 5 > 3^x = 5
y = log_{3} 2 > 3^y = 2
let log_{3} 60 = z  3^z = 60
3^z = 60
= (3)(2)(2)(5)
= (3^0)(3^y)(3^y)(3^x)
= 3(1+y+y+x)
= 3^(x+2y+1)
then z = x+2y+1
log_{3}60 = x+2y+1