Logbase3(4X +1) -Logbase3(3X -5) =2

To solve the equation Logbase3(4X + 1) - Logbase3(3X - 5) = 2, we can use the properties of logarithms.

Step 1: Combine the logarithms using the quotient rule. According to the quotient rule of logarithms, LogbaseA(B) - LogbaseA(C) = LogbaseA(B / C). Applying this rule, we have:

Logbase3((4X + 1) / (3X - 5)) = 2

Step 2: Rewrite the equation in exponential form. In exponential form, the equation will be:

3^2 = (4X + 1) / (3X - 5)

Step 3: Simplify the equation. Square 3:

9 = (4X + 1) / (3X - 5)

Step 4: Cross-multiply to eliminate the fractions:

9 * (3X - 5) = 4X + 1

27X - 45 = 4X + 1

Step 5: Combine like terms:

27X - 4X = 1 + 45

23X = 46

Step 6: Solve for X:

X = 46 / 23

X = 2

So, the solution to the equation Logbase3(4X + 1) - Logbase3(3X - 5) = 2 is X = 2.

To solve the given equation, we'll use logarithmic properties and algebraic manipulation. Here's how we can proceed:

Step 1: Apply logarithmic properties
Using the property of logarithms, we can rewrite the equation as follows:

logbase3(4X + 1) - logbase3(3X - 5) = 2

Step 2: Combine the logarithmic terms
Using the property of logarithmic subtraction, the equation can be further simplified:

logbase3[(4X + 1) / (3X - 5)] = 2

Step 3: Rewrite the equation in exponential form
Converting the equation back to exponential form will help us solve for X. In exponential form, the base 3 is raised to the power of 2, equal to the expression inside the logarithm:

3^2 = (4X + 1) / (3X - 5)

Step 4: Solve the equation
Multiply both sides of the equation by (3X - 5) to eliminate the fraction:

9(3X - 5) = 4X + 1

Expanding and simplifying the equation:

27X - 45 = 4X + 1

Combine like terms:

27X - 4X = 1 + 45

23X = 46

Divide both sides by 23 to isolate X:

X = 46 / 23

Simplifying the fraction:

X = 2

Therefore, the value of X that satisfies the equation logbase3(4X + 1) - logbase3(3X - 5) = 2 is X = 2.

Let's solve this logarithmic equation step by step.

Using the logarithmic properties:
1. Logbase3(4X + 1) - Logbase3(3X - 5) = Logbase3((4X + 1)/(3X - 5))

Rearranging the equation:
2 = Logbase3((4X + 1)/(3X - 5))

Now, we can rewrite the equation in exponential form:
3^2 = (4X + 1)/(3X - 5)

9 = (4X + 1)/(3X - 5)

Cross-multiplying:
9(3X - 5) = 4X + 1

27X - 45 = 4X + 1

Subtracting 4X from both sides:
27X - 4X - 45 = 1

Simplifying the equation:
23X - 45 = 1

Adding 45 to both sides:
23X = 46

Dividing both sides by 23:
X = 2

Therefore, the solution to the equation is X = 2.