Algebra 1
posted by Kris on .
In 2000, the internatonal price of gold was $270 per ounce, and the price of silver was $5 per ounce. How much silver could be mixed with 9 oz of gold to obtain a mixture that costs $164 per ounce?

total weight of silver + gold = s+g
total value of s+g = 5s + 270g
So, now for the mixture
5s + 270g = (s+g)*164
Bu, g=9
5s + 270*9 = 164(s+9)
5s + 2430 = 164s + 1476
159s = 954
s = 6