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April 24, 2014

April 24, 2014

Posted by **FAKAAPO** on Wednesday, September 21, 2011 at 7:15am.

college education is important to succeed in the business world. If a random sample of five Americans

is s selected, find these probabilities.

(a) Exactly two people will agree with that statement.

(b) At most three people will agree with that statement.

(c) At least two people will agree with that statement.

(d) Fewer than three people agree with that statement.

- PROBABILITY -
**drwls**, Wednesday, September 21, 2011 at 8:14amCalculate the probabilities that there will be 0,1,2,3,4 and 5 persons that agree.

P(5) = (0.4)^5*[5!/(0!*5!]= 0.4^5

= 0.01024

P(0) = (0.6)^5*[5!/(0!*5!]= (0.6)^5

= 0.07776

P(1) = (0.4)*(0.6)^4*[5!/(4!*1!)]

= 0.25920

P(2) = (0.4)^2*(0.6)^3*[5!/(3!*2!)]

= 0.34560

etc. Calculate P(3) and P(4) using the same formula, and use the results to answer the questions for (a) through (d).

For (a), the answer is P(2) = 0.3456

For (d), the answer is P(0) + P(1) + P(2) = 0.68256

- PROBABILITY -
**Reiny**, Wednesday, September 21, 2011 at 8:22amI= important

N=not important

P(i) = 60/100 = 3/5

P(N) = 2/5

a) P(2out of5 for I) = C(5,2)(3/5)^2 (2/5)^3 = 10(9/25)(8/125) = 144/625 or .2304

..

d) fewer than three agree --> 0outof5 or 1outof5 or 2outof5 will agree

= C(5,0)(3/5)^0 (2/5)^5 + C(5,1)(3/5)^1 (2/5)^4 + C(5,2)(3/5)^2 (2/5)^3

= 1(1)(32/3125 + 5(3/5)(16/625) + 10(9/25)(8/125)

= 32/3125 + 48/625 + 144/625

= 992/3125 or .31744

do b) and c) the same way

- PROBABILITY -
**Anonymous**, Thursday, September 22, 2011 at 9:33pmthere are 4 dimes, 4 nickels,

and 2 quarters.

In how many possible ways can the selection be made so that

the value of the coins is at least 25 cents?

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