Thursday

October 30, 2014

October 30, 2014

Posted by **henry baliz** on Friday, February 18, 2011 at 6:37pm.

- pre calculus -
**MathMate**, Friday, February 18, 2011 at 8:24pmf(x)=-x^2-1

f(6)=-(6)^2-1=-36-1=-37

f(-6)=-(-6)^2-1=-36-1=37

So we see that for this particular function, f(6)=f(-6).

In fact, since f(x) is an even function (consisting of even powers of x), this property of f(x)=f(-x) is true for all values of x.

You can try out other pairs, such as f(2) and f(-2) to verify this property.

**Answer this Question**

**Related Questions**

math - i need some serious help with limits in pre-calc. here are a few ...

Pre- Calculus - Evaluate the trig function tan33degress

Pre Calculus - Use a calculator to evaluate csc 3ð/14 A. 1.604 B. 1.279 C. 47....

pre calculus - evaluate if possible the function at the given values(s) of the ...

Pre-Calculus/Calculus - I am too embarassed to ask this Calculus (really pre-...

Pre Calculus - Pre Calculus why is sin(-20)/cos 380 equal to tan (-200)

Pre-Calculus - Evaluate the expression under the given conditions.? show work ...

pre calc - evaluate the trigonometric function of the given quadrantal angle. ...

Pre-Calculus - I am in Honors Pre-Calculus and am having a hard time ...

Pre Calculus - Evaluate log b {square root of 10b}, given that log b 2 = 0.3562 ...