Posted by **henry baliz** on Friday, February 18, 2011 at 6:37pm.

let f(x)= -x^2 - 1. evaluate f(x)at x=6, -6

- pre calculus -
**MathMate**, Friday, February 18, 2011 at 8:24pm
f(x)=-x^2-1

f(6)=-(6)^2-1=-36-1=-37

f(-6)=-(-6)^2-1=-36-1=37

So we see that for this particular function, f(6)=f(-6).

In fact, since f(x) is an even function (consisting of even powers of x), this property of f(x)=f(-x) is true for all values of x.

You can try out other pairs, such as f(2) and f(-2) to verify this property.

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