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July 31, 2014

July 31, 2014

Posted by **azam** on Sunday, February 21, 2010 at 10:26am.

- maths - challenge -
**Reiny**, Sunday, February 21, 2010 at 10:44ama=1, and r=2

so t_{n}= a(r^(n-1))

100000 = 1(2)^(n-1)

log 100000 = log(2)^(n-1)

n-1 = log100000/log2

n-1 = 16.6

n = 17.6 or appr 18 days

check:

1,2,4,8,16,32,64,128,256,512,1024,2048,4096,8192,16384,32768,65536,131072

on the 17th he is under,

on the 18th day he is over.

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