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December 18, 2014

December 18, 2014

Posted by **Anna** on Saturday, November 14, 2009 at 5:24pm.

- Probability -
**Reiny**, Saturday, November 14, 2009 at 5:33pmprob for Joan, then Jim = (4/11)(3/10) = 12/110 = 6/55

prob for Jim, then Joan = 6/55

so prob = 6/55 + 6/55 = 12/55

or

using combinations,

prob they both pick red

= C(4,1)xC(3,1)/C(11,2) = 12/55

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