Posted by **Anna** on Saturday, November 14, 2009 at 5:24pm.

A jar contains four red, four yellow, and three green jelly beans. If Joan and Jim take one jelly bean each, the probability that they both take a red jelly bean is?

- Probability -
**Reiny**, Saturday, November 14, 2009 at 5:33pm
prob for Joan, then Jim = (4/11)(3/10) = 12/110 = 6/55

prob for Jim, then Joan = 6/55

so prob = 6/55 + 6/55 = 12/55

or

using combinations,

prob they both pick red

= C(4,1)xC(3,1)/C(11,2) = 12/55

## Answer this Question

## Related Questions

- Math - Assume a box contains three red jelly beans and two green ones. We ...
- math again - You have a bag with 60 black jelly beans and 240 red ones. a) If ...
- algebra - You have a bag with 60 black jelly beans and 240 red ones. a) If you ...
- probability and counting - (1 pt) A box contains 25 yellow, 28 green and 38 red ...
- Math - A box has 8 blue and 5 green jelly beans. A bag has 6 blue and 8 green ...
- math - A jar contains some red and some yellow jelly beans. If a child ate 1 red...
- math - if jay eats 1/3 of jelly beans and jack 1/4 of the jelly bean leveing ...
- Maths - A music store offers a prize to a customer who can guess the closest, ...
- math - A music store offers a prize to a computer who can guess the closest, the...
- math - The ratio of red jelly beans to yellow jelly beans in a dish is 2:3. If I...

More Related Questions