A jar contains jelly beans. There are
six yellow jelly beans,
six blue jelly beans and
five green jelly beans. You randomly take two jelly beans out to eat. What is the probability that one jelly bean is red and the other jelly bean is green? Write your answer as a fraction. You do not need to simplify.
The total number of jelly beans in the jar is 6 + 6 + 5 = 17.
To find the probability of selecting one red jelly bean and one green jelly bean, we need to calculate the number of favorable outcomes and divide it by the total number of possible outcomes.
The number of favorable outcomes is the number of ways to choose one red jelly bean out of the 6 red jelly beans, multiplied by the number of ways to choose one green jelly bean out of the 5 green jelly beans. This can be represented as 6 * 5 = 30.
The total number of possible outcomes is the number of ways to choose two jelly beans out of the 17 jelly beans, which can be calculated using combinations. This can be represented as C(17, 2) = 136.
Therefore, the probability of selecting one red jelly bean and one green jelly bean is 30/136.
The answer is 30/136.