A jar contains jelly beans. There are
4
4 red jelly beans,
3
3 blue jelly beans and
6
6 green jelly beans. You randomly take two jelly beans out to eat. What is the probability that one jelly bean is red and the other jelly bean is green? Write your answer as a fraction. You do not need to simpli
The total number of jelly beans in the jar is 4 + 3 + 6 = 13.
The probability of selecting a red jelly bean first is 4/13.
After selecting a red jelly bean, the total number of jelly beans left is 13 - 1 = 12, and the number of green jelly beans left is 6.
The probability of selecting a green jelly bean second, given that a red jelly bean was selected first, is 6/12 = 1/2.
Therefore, the probability of selecting one red jelly bean and one green jelly bean is (4/13) * (1/2) = 4/26 = 2/13.