Homework Help: Physics

Posted by Ellie on Thursday, November 12, 2009 at 6:21am.

Read the activity 2-1:Force and Pressure in the lab manual (pages 167-168). As described in the manual, consider a 10 cc syringe is connected to a 50 cc syringe. Information of the syringes are as follows:
(mass of 10 cc piston) = 16 g
(mass of 50 cc piston) = 60.6 g
(diameter of 10 cc piston) = 14.7 mm
(diameter of 50 cc piston) = 28.0 mm.

(a) What is the pressure exerted by the 10 cc piston onto the air underneath?
kPa

(b) If a 50 g mass is placed on the 10 cc piston, what is the pressure exerted by the 10 cc piston onto the air underneath?
kPa

(c) If a force probe is attached to the 50 cc piston, what do you expect will be the force measurement while a 50 g mass is placed on the 10 cc piston?
N

(d) Now, the 50 g mass is removed from the 10 cc piston, and another force probe is attached to the 10 cc piston. Now both 10 cc piston and 50 cc piston have force probes attached to them. Consider that the 10 cc piston is pressed down with a force FA, and let's call FB to be the force measured by the force probe on the 50 cc piston. If you write FA as a function of FB, what is the slope of the function?

totally stumped help anyone?

Physics - Ellie, Thursday, November 12, 2009 at 7:00am
ok so. I solved first part with F/A i got .9239 kPa.

second part i solved to i just added the forces. I got 3.811 kPa.

The last two i am having difficulty with....
Physics - Ellie, Thursday, November 12, 2009 at 7:05am
So since i know F/A=F/A

I'm just confused on how it affects one another....
Physics - Ellie, Thursday, November 12, 2009 at 7:08am
i tried 646.8/169.71=F2/615.752 and tried solving for F but i am getting 2346.759 and it just not right..
Physics - Ellie, Thursday, November 12, 2009 at 7:14am
should not F2=F1*A2/A so F2=646.8*(615.752/169.71)

F2=2346.759
Physics - drwls, Thursday, November 12, 2009 at 9:21am
The important thing to remember is that the pressure is uniform throughout the fluid (air?), so that the ratio of piston weight (plus applied force) to piston area is the same on both sides (i.e., both syringes) . You seem to have grasped that already.
Physics - bobpursley, Thursday, November 12, 2009 at 9:25am
Lets take the small pisiont with its 50 g nass

.05g/PI(.0147)^2/4 = Forcereadin/PI(.027)^2/4

or

forcereading=.05g*(.027/.0147)^2

Answer this Question

Related Questions

Physics - Read the activity 2-1:Force and Pressure in the lab manual (pages 167-...
Ap Physics - Read the activity 2-1:Force and Pressure in the lab manual (pages ...
Lab in general - I just read my syllabus for lab and I am kind of shocked at ...
COM 135 - Prewriting,writing, ReWriting are 3 main steps in the technical ...
COM 135 - how you would use these steps to create the manual mentioned in this ...
business - You are a technical writer in a large company who is working on a ...
English - You are a technical writer in a large company, working on a training ...
Com 135 - Read the following scenario: As a customer service manager for a local...
computer science - Final Project Overview and Timeline Final Project Overview ...
Business Communication - You are a technical writer in a large company, working ...

For Further Reading

First Name:
School Subject:
Answer: