Arlene read 30 pages. That is 10 pages more than half of the pages Taylor read. How many pages did Taylor read?
Write an equation in the form px+q=r to represent this problem.
Let x represent the number of pages Taylor read.
Half of the pages Taylor read is x/2.
10 pages more than half of the pages Taylor read is (x/2) + 10.
The equation to represent this problem is 30 = (x/2) + 10.
Let's assume that Taylor read x number of pages.
Given that Arlene read 30 pages and that is 10 pages more than half of the pages Taylor read, we can write the equation as follows:
30 = (x/2) + 10
Rewriting the equation in the form px + q = r:
(x/2) + 10 = 30
Multiplying both sides of the equation by 2 to eliminate the fraction:
2 * ((x/2) + 10) = 2 * 30
x + 20 = 60
Subtracting 20 from both sides of the equation:
x + 20 - 20 = 60 - 20
x = 40
Therefore, Taylor read 40 pages.
The equation in the form px + q = r is:
0.5x + 10 = 30
To solve this problem, we can set up the equation based on the given information.
Let's define:
Arlene's pages read = A
Taylor's pages read = T
According to the problem, Arlene read 30 pages, which can be represented as:
A = 30
Also, it is stated that Arlene read 10 pages more than half of the pages Taylor read. Mathematically, this can be expressed as:
A = (1/2)T + 10
Combining both equations, we have:
30 = (1/2)T + 10
To express this equation in the form px + q = r, we start by isolating the variable T.
Subtracting 10 from both sides of the equation, we get:
30 - 10 = (1/2)T
20 = (1/2)T
To eliminate the fraction, we multiply both sides of the equation by 2:
2 * 20 = 2 * (1/2)T
40 = T
So, Taylor read 40 pages.
In the form px + q = r, the equation representing this problem is:
(1/2)T + 10 = 30